| Flaknker | Sunday, 8th April 2007 2:42pm - No.1092 |
i may seem stupid 2 ask such questions here but this is the only way i found inorder to contact u as ur answers r marvellous
- first i want to make a high voltage switch (about 20-30kv) without time delay or much time-energy consumption of the pulse discharged
- i have read the subject about the ignition coil driver i find it money consuming compared with a capacitor - SCR pulsator connected ot the primary - the question is how to connect them (the cap.& scr)
please please if u can't answer me here forward it to "thechaosdrone@yahoo.com"
please |
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| RMCybernetics | Sunday, 8th April 2007 3:54pm - No.1096 |
You would use an SCR in a similar way to how the MOSFET is wired in the pulse controller circuit. The main difference is that an SCR will not switch off until the voltage drops to zero.
If you want to switch 20-30kV with a silicon device like an SCR, you will find that this can be quite expensive. This is why a spark gap is used in most Tesla Coils. |
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| flanker | Saturday, 14th April 2007 12:17pm - No.1159 |
how u doin (by the way i love u)
i wanted to ask some questions about the spark gap (we talked about formerly)
just some trivial ideas wanna know if they could work or not
could applying a steady capacitive dc field from an external cicuit to the spark gap decrease its resitivity for the HV impulse
how could i calculate the spark gap resistivity
what about presetting of a very isolating material(ensures close distance) going continuous with a metal or so and moved perpindicularly very quickly in the field
instead of the air and the metallic ball offered in this side, it could be a rectangulare piece of plastic continuous with a very good conductor
very thankful for u after all |
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| RMCybernetics | Saturday, 14th April 2007 1:04pm - No.1160 |
If you could describe your application I may be able to help better.
You can't really do a lot change the resistance of the spark gap because it is just a product of the voltage, spacing, and air/gas mix. You could possibly change the gas to Argon for example, but this has lower ionization voltage so the switching would be less abrupt. Another way would be to reduce the pressure inside the gap.
I don't know how you might calculate the resistance, but it will be a dynamic (changing) value. When the arc is fully formed, the resistance will be very low.
Are you describing some sort of rotary spark gap here? Insulating the spark gap electrodes will reduce leakage and allow you to trigger the spark manually (when you remove the insulation) rather than when the breakdown voltage of the air gap is reached.
One method of improving spark gap performance is to use magnetic quenching. This is where strong magnets are placed either side of the gap so the magnetic field crosses at 90 degrees to the electric field. With this setup, the arc will be pushed outward as soon as it forms. This is because when the current begins to flow it creates a magnetic field which will react against the field from the magnets. This has the effect of switching off your spark gap very quickly. |
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| flanker | Wednesday, 18th April 2007 12:25pm - No.1182 |
| first here is my idea but put in ur mind am an amateur in the first place |
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| flanker | Wednesday, 18th April 2007 12:42pm - No.1183 |
 may peace be upon u
i have concluded that in the first place it does need very fast mechanical displacement wether using a magnet or my damn design , it is how fast the opposithion will decay to let the current grow , so we must start thinkin in the light of this ( iam waiting ur ideas )
i wanted to show u this image
it would be massive for ur plasma globe u formerly offered on the site the capacitor's impedance should be about 3000 ohms
but my problem in this design that where i live the dimmer switch is very expensive and am askin u for an alternative that i can make or cheap to buy ( cuz i donno how does the dimmer really work) i just know it is a sorta variable "power"inputter or so .
the whole thing about the spark gap is that a making a super capacitor and i want it to discharge so fast in nano seconds for a very powerful metal propeller .... so far i have chosen PET for the design dielectric cuz its (C*breakdown voltage) is very high about 22000 , if u can recommend me a better one please do
r u only one engineer who answer all the forums or wat cuz if u r so u must be a genius
waitin ur response |
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| RMCybernetics | Wednesday, 18th April 2007 10:05pm - No.1184 |
A dimmer switch works by 'chopping' the current flowing through light bulb. It basically switches the light repeatedly on and off at a fixed frequency. When you turn the switch (a potentiometer) the ratio of on time to off time is changed. To make the light brighter you increase the on time therefore increasing the average power. This is known as pulse width modulation.
The rate at which you will be able to discharge your capacitor will mainly be determined by the inductive reactance of your system. You will need to keep wires as short, wide and straight as possible. The same for the capacitor. Use large conductors with as few bends as possible.
Most questions are answered by me but some are answered by other scientists if they can provde a better answer.
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| flanker | Friday, 20th April 2007 8:04pm - No.1188 |
how u doin
i have read an article about high voltage discarging and there were mentioned about the high voltage switch that "magnetrons" ,"klystrons" & "vircators" can be used
r those things applicable for me and how can i get make or use them (and how does they work in the first place)
about the commercial dimmer shown previously in the image -could it be used with dc input or it just works with ac
also i would be very thankful if u could give me a link or so to a site where i can fine about the breakdown voltages of substance (for the capacitpr ofcourse)
really appreciate u |
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| RMCybernetics | Tuesday, 24th April 2007 1:55pm - No.1198 |
Klystrons, magnetrons are generally used for microwave amplification. They are vacuum devices like the old style 'valves' that were used in radios. A amgnetron can be found in a microwave oven. It is used as a resonant cavity for generating the microwaves. None of these devices would suit your application.
A dimmer will work with an ac input. You would need a pulse width modulator for DC.
Google will adequatley answer your last question. Use "breakdown voltages of dielectrics". There's plenty of useful data there. |
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| Flanker | Saturday, 28th April 2007 8:16pm - No.1206 |
peace
am now searching as u asked for but i found some interesting results as avalanche diodes (can hold up to 4kV) (could many of it be connected in series and operated "on" by an external cap of about 1kV in series) and avalanche-photodiodes wat about them ?also wat about zener breakdown ?
or could i directly force the main cap to arc by the same way and after the first arc there wouldn't be enuf energy for arcing back in the LC and it would continue to resonate
but i didn't find much about VBreakdown tables
However,can't the ignition coil be driven by resonance as does the TV flyback by winding a 2nd primary to the transistor's base-emitter circuit coil from around its exterior.(operating on a DC)
recently have fixed and modified a puffed up PC powersupply and turned it into a lab PS
it's terminals go as follows: 5V/8A , -5V/8A , 12V/20A & -12V/30A
could the 2N3055 power-transistor be powered upon these terminals & their combinations or it would just get burned(can their be Rs to prevent so) ,(would be marvellous if u have its fact sheet)
really without a bit of hipocracy ,i swear am very thankful to a massive extent ,really can't describe it
u'r just sophisticated
peace again ... by the way wat can i call u |
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| RMCybernetics | Sunday, 29th April 2007 11:45pm - No.1207 |
Photodiodes are usually used with signal level currents. Other types of diodes will be expensive if they are to withstand a large current pulse from the discharging of a capacitor.
It is possible to wrap a few turns of wire around the case of an ignition coil to be used as feedback for a flyback driver.
the 2n3055 is rated for a maximum of 15A. |
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| flanker | Wednesday, 9th May 2007 10:35pm - No.1244 |
hi
can i half-wave rectify high AC voltage simply with a series of 1N4007
by the condition that every single diode adds a back-blockage of 1000 volts and all of them can pass a current less than 0.7 Amp
when measuring the outputs of the dimmer's circuit can i simply calculate it or i only have got to use a current divider and a voltage divider and a simple multimeter
about the hi voltage switch i talked about before it is a continuous cuboidal shape consisting of two equal cubes of a bad conductor and a good conductor fused together and it is moved swiftly between the high voltage electrodes.hope u can imagine it.
if it's beginning to be hard to bear u just can say it cuz am feeling so ... |
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| RMCybernetics | Wednesday, 9th May 2007 11:37pm - No.1245 |
The diodes will not all work at the exact same time. This can lead to an uneven voltage distribution between the diodes which can cause then to fail. You can get around this problem by adding about 2M ohm resistor in parallel with each diode.
Measuring the output would be more accurate ad easier.
Can you draw a diagram of your HV switch? |
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| Flanker | Thursday, 10th May 2007 10:52pm - No.1249 |
 peace..
i have uploaded it on the following link "http://img263.imageshack.us/img263/1273/sparkyx0.jpg" as i think it will fail again in being forwarded.
the idea is to move swiftly and very rapidly the intermediate part up/down for switching , but am still thinkin about such an efficient way of movement ,Almst the same idea of obstacling by a magnet and movin it as u formerly recommended |
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| Flanker | Thursday, 10th May 2007 11:02pm - No.1250 |
sorry ..
just forgot to ask another question :
when charging the HV Cap. by the talked about diodes series how can i know when exactly is the cap voltage is equal to the source voltage (i.e:the cap is full or almost full)
can i attach a LED in sorta way or there is someother way
sorry again about the 2Mohms resistors wat is their wattage. |
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| RMCybernetics | Friday, 11th May 2007 1:43am - No.1252 |
Making a wheel from the dielectric with several copper pieces embedded in it would make a good rotary type switch.
The current flowing from your charging supply will drop to near zero when the capacitor is charged. You could use an ammeter to indicate this.
The 2M resistors only need a low wattage rating because they are just being used to distribute the voltage and not much power. The typical 1/4 watt ones would be fine. |
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| bobby | Saturday, 2nd June 2007 8:27am - No.1362 |
Hi, wow, nice site!
i have a question:
How is it possible to make a permanent magnet vibrate, i've read that a pieso-something can work, i'm trying to replicate a certain experiment of faraday i think,
thanks in advance
keep up the imaginations raving |
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| RMCybernetics | Monday, 4th June 2007 12:28am - No.1365 |
| Maybe a piezoelectric transducer is what you need. You could place the magnet onto something like this cymatics device which is used for making faraday waves. |
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| Flanker | Monday, 9th July 2007 1:08am - No.1420 |
could i use sorta a huge massive efficient relay
as the high voltage switch and if i can please recommend me a particular one
if am making a voltage divider for high voltage source , wat should be the wattage of the resistances
in the dimmer circuit shown above from where should i get the ground for the high voltage output,i think of using the water tab cuz ofcourse it is AC which is going on the 2 primary coil terminals so i can use neither of them, can i ?
and thanks much
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| RMCybernetics | Monday, 9th July 2007 9:25am - No.1423 |
This supplier of high voltage relays makes a nice range of large HV relays.
You can caluclate the watage of your resistors using Ohms/Watts law. Using the square of the voltage across each resistor divided by its resistance will give you the minimum power rating needed.
The opposite side of the secondry winding of an ignition coil is internally connected to the -ve input termainal. You can take your HV output from between this and the output terminal. |
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| Flank | Friday, 13th July 2007 4:13am - No.1436 |
hi
am running an electrolyte and i have to pass only a certain voltage through it ,i have tried to make a voltage divider but the pot. got burnt cuz of the high power ,and high power pot.s are expensive here , could i connect in series a low current pot with a high wattage (about 10 ohms) common resistance to dec the power load on the variable resistance or wat should i do ?
very thankful |
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| RMCybernetics | Friday, 13th July 2007 9:38pm - No.1441 |
Use a voltage regulator IC. They are low cost and will deliver a reasonable level of power.
Most voltage regulators are set to a specific voltage, but you can also get adjustable ones where you could use your low power pot to adjust its output. |
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| Flank | Monday, 16th July 2007 12:56am - No.1450 |
am sorry but this may be only the second time i hear about IC Vregulator,how should i connect it and how to use the variable resistance with it.
wat intervals of power does it operate on ?
thanks |
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| RMCybernetics | Tuesday, 17th July 2007 11:06pm - No.1460 |
There are thousands of different types. You will need to refer to the manufacturers datasheet for for instructions.
Google 'adjustable voltage regulator' for some examples.
This L200 regulator may work for you. The datasheet also includes example schematics. |
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| Flanker | Thursday, 19th July 2007 9:47pm - No.1478 |
| i succeeded in wat i formerly assumed for voltage dividing , but i noticed that as the reaction proceeds forward the resistance of the electrolyte shifts in a considerable way , so the voltage values changes , if i dont want to watch the meters all the time and to sit on the pot. wat can i use , recommend wat to fix the voltage at a certain level for a power not less than 15watts |
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| RMCybernetics | Friday, 20th July 2007 12:06am - No.1481 |
This is what a voltage regulator will do. It keeps the voltage at a set level regardless of the resistance of the load (your electrolyte).
If you want to maintain a constant rate of reaction then it is actually the current you will need to regulate. Devices for this are often called 'constant current diode' |
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| Flanker | Saturday, 21st July 2007 3:20am - No.1486 |
am sorry for bothering u too much, but i do cuz i really think that u could help me cuz this electrolytic rection is being set for a patent,
this reaction is at a voltage range of 1-1.2volts
and never mind of the intensity
as long as it's constant, the power may range from 250-12.5w according to the power supply am using,according to the latter info can u help me in any specifications of the regulator used.
really appriciating ur help wether u can find this one or not |
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| RMCybernetics | Saturday, 21st July 2007 3:55pm - No.1487 |
I can't really help you any more on this I'm afraid. This section really is for questions on the page subject of 'Contact Electrification'.
I simply can not continue to provide help for free for your own personal projects. I can design whatever electronic systems you desire, but you must pay for the time and resources. See the Custom Electronics page for details. |
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| koko | Tuesday, 21st August 2007 2:30am - No.1629 |
this subject over here is quite simillar to the electret effect,could the using of two different material of those (incontact with each other) produce the alleged "free energy" from ionic air molecule (+ve ones)and how this plane could be connected to the ground to charge a cap.
would be finer if with drawing |
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| RMCybernetics | Tuesday, 21st August 2007 10:25am - No.1632 |
| The electret effect is actually quite different as it is a quasi-permanent dipole moment in the charge distribution in a material. Contact electrification involves the making and breaking of ionic bonds between dissimilar materials. Maybe a tiny amount of contact electrification could occur from air hitting another material. Collecting it would probably be done with something similar to an electrohydrodynamic thruster. |
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| koko | Thursday, 23rd August 2007 12:17am - No.1643 |
| i mean this permenant charge as i understood should be between the two sides of the material making a positive and a negative pole as a magnet but with an electric field , could this be achieved from fusing a dielectric between two of those different materials after getting them charged, if i misunderstand the whole matter or am i right |
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| RMCybernetics | Thursday, 23rd August 2007 9:50am - No.1646 |
Not exactly. The dipole moment would be an induced one rather than a permanent one caused by the molecular structure of the material its self.
Dielectrics also have a very small level of conductivity so any induced voltage would leak away eventually.
Man made electrets are often formed by setting a liquid compound in the presence of a high electric field. This way the molecules align to the field and set into position when it hardens. |
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| W.B. | Friday, 14th December 2007 12:00am - No.2341 |
| Ye Gods! Just followed the `Flanker` thread. You deserve V.C. + Nobel Prize for A)Keeping a straight face; B) Staying sane; C) Simply not telling him to `go` The guy is thick, he`ll kill himself. Regards. W.B. |
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| Hamish | Wednesday, 26th March 2008 4:52am - No.2647 |
 i made a smal VDG about a year ago, stole a baking tin off mum for a sphere, i was getting 12cm spark jumps off it. you could smell the ozone being produced by it too |
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| Tassaduq | Thursday, 10th April 2008 5:49am - No.2703 |
 Do any one think if we use two metal rollers in a van de graff generater with +ve and -ve terminals of dc adopter attached to. Then we won't to use glass or plastic. |
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| RMCybernetics | Thursday, 10th April 2008 12:42pm - No.2704 |
| No, This wont work. |
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